Optimal. Leaf size=145 \[ \frac{(5 a B+4 b C) \tan ^3(c+d x)}{15 d}+\frac{(5 a B+4 b C) \tan (c+d x)}{5 d}+\frac{3 (a C+b B) \tanh ^{-1}(\sin (c+d x))}{8 d}+\frac{(a C+b B) \tan (c+d x) \sec ^3(c+d x)}{4 d}+\frac{3 (a C+b B) \tan (c+d x) \sec (c+d x)}{8 d}+\frac{b C \tan (c+d x) \sec ^4(c+d x)}{5 d} \]
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Rubi [A] time = 0.203111, antiderivative size = 145, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 6, integrand size = 38, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.158, Rules used = {4072, 3997, 3787, 3767, 3768, 3770} \[ \frac{(5 a B+4 b C) \tan ^3(c+d x)}{15 d}+\frac{(5 a B+4 b C) \tan (c+d x)}{5 d}+\frac{3 (a C+b B) \tanh ^{-1}(\sin (c+d x))}{8 d}+\frac{(a C+b B) \tan (c+d x) \sec ^3(c+d x)}{4 d}+\frac{3 (a C+b B) \tan (c+d x) \sec (c+d x)}{8 d}+\frac{b C \tan (c+d x) \sec ^4(c+d x)}{5 d} \]
Antiderivative was successfully verified.
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Rule 4072
Rule 3997
Rule 3787
Rule 3767
Rule 3768
Rule 3770
Rubi steps
\begin{align*} \int \sec ^3(c+d x) (a+b \sec (c+d x)) \left (B \sec (c+d x)+C \sec ^2(c+d x)\right ) \, dx &=\int \sec ^4(c+d x) (a+b \sec (c+d x)) (B+C \sec (c+d x)) \, dx\\ &=\frac{b C \sec ^4(c+d x) \tan (c+d x)}{5 d}+\frac{1}{5} \int \sec ^4(c+d x) (5 a B+4 b C+5 (b B+a C) \sec (c+d x)) \, dx\\ &=\frac{b C \sec ^4(c+d x) \tan (c+d x)}{5 d}+(b B+a C) \int \sec ^5(c+d x) \, dx+\frac{1}{5} (5 a B+4 b C) \int \sec ^4(c+d x) \, dx\\ &=\frac{(b B+a C) \sec ^3(c+d x) \tan (c+d x)}{4 d}+\frac{b C \sec ^4(c+d x) \tan (c+d x)}{5 d}+\frac{1}{4} (3 (b B+a C)) \int \sec ^3(c+d x) \, dx-\frac{(5 a B+4 b C) \operatorname{Subst}\left (\int \left (1+x^2\right ) \, dx,x,-\tan (c+d x)\right )}{5 d}\\ &=\frac{(5 a B+4 b C) \tan (c+d x)}{5 d}+\frac{3 (b B+a C) \sec (c+d x) \tan (c+d x)}{8 d}+\frac{(b B+a C) \sec ^3(c+d x) \tan (c+d x)}{4 d}+\frac{b C \sec ^4(c+d x) \tan (c+d x)}{5 d}+\frac{(5 a B+4 b C) \tan ^3(c+d x)}{15 d}+\frac{1}{8} (3 (b B+a C)) \int \sec (c+d x) \, dx\\ &=\frac{3 (b B+a C) \tanh ^{-1}(\sin (c+d x))}{8 d}+\frac{(5 a B+4 b C) \tan (c+d x)}{5 d}+\frac{3 (b B+a C) \sec (c+d x) \tan (c+d x)}{8 d}+\frac{(b B+a C) \sec ^3(c+d x) \tan (c+d x)}{4 d}+\frac{b C \sec ^4(c+d x) \tan (c+d x)}{5 d}+\frac{(5 a B+4 b C) \tan ^3(c+d x)}{15 d}\\ \end{align*}
Mathematica [A] time = 0.88028, size = 106, normalized size = 0.73 \[ \frac{45 (a C+b B) \tanh ^{-1}(\sin (c+d x))+\tan (c+d x) \left (8 \left (5 (a B+2 b C) \tan ^2(c+d x)+15 (a B+b C)+3 b C \tan ^4(c+d x)\right )+30 (a C+b B) \sec ^3(c+d x)+45 (a C+b B) \sec (c+d x)\right )}{120 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.036, size = 213, normalized size = 1.5 \begin{align*}{\frac{2\,Ba\tan \left ( dx+c \right ) }{3\,d}}+{\frac{Ba\tan \left ( dx+c \right ) \left ( \sec \left ( dx+c \right ) \right ) ^{2}}{3\,d}}+{\frac{aC \left ( \sec \left ( dx+c \right ) \right ) ^{3}\tan \left ( dx+c \right ) }{4\,d}}+{\frac{3\,C\sec \left ( dx+c \right ) a\tan \left ( dx+c \right ) }{8\,d}}+{\frac{3\,aC\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{8\,d}}+{\frac{Bb\tan \left ( dx+c \right ) \left ( \sec \left ( dx+c \right ) \right ) ^{3}}{4\,d}}+{\frac{3\,Bb\tan \left ( dx+c \right ) \sec \left ( dx+c \right ) }{8\,d}}+{\frac{3\,Bb\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{8\,d}}+{\frac{8\,Cb\tan \left ( dx+c \right ) }{15\,d}}+{\frac{Cb \left ( \sec \left ( dx+c \right ) \right ) ^{4}\tan \left ( dx+c \right ) }{5\,d}}+{\frac{4\,C \left ( \sec \left ( dx+c \right ) \right ) ^{2}b\tan \left ( dx+c \right ) }{15\,d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 0.968834, size = 270, normalized size = 1.86 \begin{align*} \frac{80 \,{\left (\tan \left (d x + c\right )^{3} + 3 \, \tan \left (d x + c\right )\right )} B a + 16 \,{\left (3 \, \tan \left (d x + c\right )^{5} + 10 \, \tan \left (d x + c\right )^{3} + 15 \, \tan \left (d x + c\right )\right )} C b - 15 \, C a{\left (\frac{2 \,{\left (3 \, \sin \left (d x + c\right )^{3} - 5 \, \sin \left (d x + c\right )\right )}}{\sin \left (d x + c\right )^{4} - 2 \, \sin \left (d x + c\right )^{2} + 1} - 3 \, \log \left (\sin \left (d x + c\right ) + 1\right ) + 3 \, \log \left (\sin \left (d x + c\right ) - 1\right )\right )} - 15 \, B b{\left (\frac{2 \,{\left (3 \, \sin \left (d x + c\right )^{3} - 5 \, \sin \left (d x + c\right )\right )}}{\sin \left (d x + c\right )^{4} - 2 \, \sin \left (d x + c\right )^{2} + 1} - 3 \, \log \left (\sin \left (d x + c\right ) + 1\right ) + 3 \, \log \left (\sin \left (d x + c\right ) - 1\right )\right )}}{240 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 0.959076, size = 397, normalized size = 2.74 \begin{align*} \frac{45 \,{\left (C a + B b\right )} \cos \left (d x + c\right )^{5} \log \left (\sin \left (d x + c\right ) + 1\right ) - 45 \,{\left (C a + B b\right )} \cos \left (d x + c\right )^{5} \log \left (-\sin \left (d x + c\right ) + 1\right ) + 2 \,{\left (16 \,{\left (5 \, B a + 4 \, C b\right )} \cos \left (d x + c\right )^{4} + 45 \,{\left (C a + B b\right )} \cos \left (d x + c\right )^{3} + 8 \,{\left (5 \, B a + 4 \, C b\right )} \cos \left (d x + c\right )^{2} + 24 \, C b + 30 \,{\left (C a + B b\right )} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{240 \, d \cos \left (d x + c\right )^{5}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (B + C \sec{\left (c + d x \right )}\right ) \left (a + b \sec{\left (c + d x \right )}\right ) \sec ^{4}{\left (c + d x \right )}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.27524, size = 446, normalized size = 3.08 \begin{align*} \frac{45 \,{\left (C a + B b\right )} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 1 \right |}\right ) - 45 \,{\left (C a + B b\right )} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 1 \right |}\right ) - \frac{2 \,{\left (120 \, B a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{9} - 75 \, C a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{9} - 75 \, B b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{9} + 120 \, C b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{9} - 320 \, B a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{7} + 30 \, C a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{7} + 30 \, B b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{7} - 160 \, C b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{7} + 400 \, B a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} + 464 \, C b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} - 320 \, B a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 30 \, C a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 30 \, B b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 160 \, C b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} + 120 \, B a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 75 \, C a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 75 \, B b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 120 \, C b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )\right )}}{{\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 1\right )}^{5}}}{120 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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